Question
Find the general solutions of the following equations: $\sqrt{3}\sec\text{x}=2$

Answer

we have, $\sqrt{3}\sec\text{x}=2$ $\Rightarrow\frac{1}{\cos\theta}=\frac{2}{\sqrt{3}}$ $\Rightarrow\cos\theta=\frac{\sqrt{3}}{2}$ $\Rightarrow\cos\theta=\cos\Big(\frac{\pi}{6}\Big)$ $\Rightarrow\theta=2\text{n}\pi\pm\frac{\pi}{6},\text{n}\in\text{z}$

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