Question
Find the interval in function -2x3 - 9x2 - 12x + 1 is increasing or decreasing:

Answer

It is given that function f(x) = -2x3 - 9x2 - 12x + 1
$\Rightarrow$ f '(x) = -6x2 - 18x + 12
$\Rightarrow$ f '(x) = -6(x2 + 3x + 6)
$\Rightarrow$ f '(x) = -6(x + 1)(x + 2)
If f '(x) = 0, then we get,
$\Rightarrow$ x = -1 and -2
So, the points x = -1 and x = -2 divides the real line into three disjoint intervals, $(-\infty,-2),(-2,-1)$ and $(-1, \infty)$ 
So, in intervals $(-\infty,-2),(-1, \infty)$
f '(x) = -6(x + 1)(x + 2) < 0
Therefore, the given function 'f ' is strictly decreasing for x < -2 and x > -1
Further, in interval (-2, -1)
f '(x) = -6(x + 1)(x + 2) > 0
Therefore, the given function (f) is strictly increasing for -2 < x < -1

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