Question
Find the largest number of $3$ digits which is a perfect square.
✓
Answer
The largest $3$ digit number is $999.$
The number whose square is $999$ is $31.61.$
Thus, the square of any number greater than $31.61$ will be a $4$ digit number.
Therefore, the square of $31$ will be the greatest $3$ digit perfect square.
$31^2= 31 \times 31 = 961$
The number whose square is $999$ is $31.61.$
Thus, the square of any number greater than $31.61$ will be a $4$ digit number.
Therefore, the square of $31$ will be the greatest $3$ digit perfect square.
$31^2= 31 \times 31 = 961$
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