Electric Current in Conductors — Physics STD 11 Science — Question

$\text{C}_\text{eq}=\big[(3\mu\text{fp}\ 3\mu\text{f})\text{s}(1\mu\text{f p}1\mu\text{f})\big]\text{p}(1\mu\text{f})$

$=\big[(3+3)\mu\text{f s}(2\mu\text{f})\big]\text{p}1\mu\text{f}$

$=\frac{3}{2}+1=\frac{5}{2}\mu\text{f}$

$\text{V}=100\text{V}$

$\text{Q}=\text{CV}=\frac{5}{2}\times100=250\mu\text{c}$

Charge stored across $1\mu\text{f}$ capacitor $=100\mu\text{C}$

C_eq between A and B is $=6\mu\text{f}=\text{C}$

Potential drop across $\text{AB}=\text{V}=\frac{\text{Q}}{\text{C}}=25\text{V}$

Potential drop across BC = 75V.