Find the power of the circuit ............ $W$
Easy
Download our app for free and get started
(c) In steady state the branch containing capacitors, can be neglected. So reduced circuit is as follows
Power $P = \frac{{{V^2}}}{R} = \frac{{{{(2)}^2}}}{4} = 1\,W$.
Power $P = \frac{{{V^2}}}{R} = \frac{{{{(2)}^2}}}{4} = 1\,W$.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1In the given circuit the current flowing through the resisitance $20$ $\mathrm{ohms}$ is $0.3$ $\mathrm{ampere}$ while the ammeter reads $0.8$ $\mathrm{ampere}.$ What is the value of $R_1$? ................ $\mathrm{ohm}$View Solution
- 2A cylindrical metal wire of length $l$ and cross sections area $S$, has resistance $R$, conductance $G$, conductivity $\sigma$ and resistivity $\rho$. Which one of the following expressions for $\sigma$ is validView Solution
- 3In order to measure the internal resistance $r_1$ of a cell of emf $E$, a meter bridge of wire resistance $R_0=50 \Omega$, a resistance $R_0 / 2$, another cell of emf $E / 2$ (internal resistance $r$ ) and a galvanometer $G$ are used in a circuit, as shown in the figure. If the null point is found at $l=72 cm$, then the value of $r_1=$ . . . . $\Omega$View Solution
- 4View SolutionThe resistivity of a wire depends on its
- 5Electric room radiator which operates at $225\, volts$ has resistance of $50\, ohms$. Power of the radiator is approximately ............... $W$View Solution
- 6In the circuit element given here, if the potential at point $B$, $V_B = 0$, then the potentials of $A$ and $D$ are given asView Solution
- 7Two wires of the same material and equal length are joined in parallel combination. If one of them has half the thickness of the other and the thinner wire has a resistance of $8\, ohms$, the resistance of the combination is equal toView Solution
- 8A wire when connected to $220\,V$ mains supply has power dissipation ${P_1}$. Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is ${P_2}$. Then ${P_2}:{P_1}$ isView Solution
- 9The resistances in the two arms of the meter bridge are $5 \,\Omega$ and $R \,\Omega$ respectively. When the resistance $R$ is shunted with an equal resistance, the new balance point is at $1.6\,l_1$. The resistance $R$ is .................. $\Omega$View Solution
- 10View SolutionOhm's law is true