Question
Find the principal and general solution of the equation: cosec x = -2

Answer

Here cosec x = - 2 $ \Rightarrow \sin x = - \frac{1}{2}$, which is negative, so x lies in third or fourth quadrant.
$\therefore \sin x=-\frac{1}{2}=-\sin 30^{\circ}=\sin \left(180^{\circ}+30^{\circ}\right) \text { or } \sin \left(360^{\circ}-30^{\circ}\right)$
$ =\sin 210^{\circ} \text { or } \sin 330^{\circ}$
$ = \sin \frac{{7\pi }}{6}$ or $\sin \frac{{11\pi }}{6}$
Hence the principal solutions are $\frac{{7\pi }}{6},\frac{{11\pi }}{6}$
Now $\sin x = - \sin \frac{\pi }{6}$
$ \Rightarrow x = n\pi + {( - 1)^n}\left( {\frac{{7\pi }}{6}} \right)$ where $n \in Z$

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