Gujarat BoardEnglish MediumSTD 11 ScienceMATHSTRIGONOMETRIC FUNCTIONS2 Marks
Question
Find the solution of sin x = – $\frac{\sqrt{3}}{2}$
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Answer
Here we have sin x = $-\frac{\sqrt{3}}{2}=-\sin \frac{\pi}{3}=\sin \left(\pi+\frac{\pi}{3}\right)=\sin \frac{4 \pi}{3}$ Hence, sin x = $\sin \frac{4 \pi}{3}$, which gives x = $n \pi+(-1)^{n} \frac{4 \pi}{3}$, where n $\in$ Z
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