Question
Find the square of : $\sqrt3 + \sqrt2$
✓
Answer
$( \sqrt3 + \sqrt2 )^2$
$= ( \sqrt3 )^2 + 2( \sqrt3 )( \sqrt2 ) + ( \sqrt2 )^2$
$= 3 + 2\sqrt6 + 2$
$= 5 + 2\sqrt6$
$= ( \sqrt3 )^2 + 2( \sqrt3 )( \sqrt2 ) + ( \sqrt2 )^2$
$= 3 + 2\sqrt6 + 2$
$= 5 + 2\sqrt6$
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