Question
Find the standard/simplest form of $\frac{-21}{27}$.
✓
Answer
Given rational number is $\frac{-21}{27}$.
For standard/simplest form,
$\frac{-21 \div 3}{27÷3}=\frac{-7}{9}$ $[\because HCF$ of 21 and 27 is 3$]$
The standard form of $\frac{-21}{27}$ is $\frac{-7}{9}$.
For standard/simplest form,
$\frac{-21 \div 3}{27÷3}=\frac{-7}{9}$ $[\because HCF$ of 21 and 27 is 3$]$
The standard form of $\frac{-21}{27}$ is $\frac{-7}{9}$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find $BC,$ if the area of the triangle $ABC$ is $36 \mathrm{~cm}^2$ and the height $AD$ is $3\ cm$ (Fig).
→→
If p = - 2 then find the value of
$-2 p^3-3 p^2+4 p+7$
→$-2 p^3-3 p^2+4 p+7$
Find the product:
$0.0146 \times 69$
→$0.0146 \times 69$
Find the radius of a circle whose circumference is $57.2\ cm.$
→Divide: $12$ by $8$
→Express the following ratios in the simplest form: $(2\ kg\ 250\ g) : (3\ kg)$
→Write $\frac{-14}{42}$ in a form so that the numerator is equal to:
42
→42
In each of the following, the measures of three angles are given. State in which cases, the angles can possibly be those of a triangle:
(i) $63^{\circ}, 37^{\circ}, 80^{\circ}$
(ii) $45^{\circ}, 61^{\circ}, 73^{\circ}$
(iii) $59^{\circ}, 72^{\circ}, 61^{\circ}$
(iv) $45^{\circ}, 45^{\circ}, 90^{\circ}$
(v) $30^{\circ}, 20^{\circ}, 125^{\circ}$
→(i) $63^{\circ}, 37^{\circ}, 80^{\circ}$
(ii) $45^{\circ}, 61^{\circ}, 73^{\circ}$
(iii) $59^{\circ}, 72^{\circ}, 61^{\circ}$
(iv) $45^{\circ}, 45^{\circ}, 90^{\circ}$
(v) $30^{\circ}, 20^{\circ}, 125^{\circ}$
Express the following numbers to the lowest form: $\frac{132}{-428}$
→