Question
Find the surface area of a cuboid whose:
Length $= 6\ dm,$ breadth $= 8\ dm,$ height $= 10\ dm.$
Length $= 6\ dm,$ breadth $= 8\ dm,$ height $= 10\ dm.$
✓
Answer
Length of cuboid $ ( 1 )=6\ dm$
Breadth $ (b) =8\ dm$
Height $(h) =10\ dm$
$\therefore$ Surface area $=2( l \times b + b \times h + h \times l )$
$=2(6 \times 8+8 \times 10+10 \times 6)\ dm ^2$
$=2(48+80+60)\ dm ^2=2 \times 188=376\ dm ^2$
Breadth $ (b) =8\ dm$
Height $(h) =10\ dm$
$\therefore$ Surface area $=2( l \times b + b \times h + h \times l )$
$=2(6 \times 8+8 \times 10+10 \times 6)\ dm ^2$
$=2(48+80+60)\ dm ^2=2 \times 188=376\ dm ^2$
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