Question
Find the trigonometric functions of : 0°
✓
Answer
Angle of measure $0^{\circ}$ :
Let $\mathrm{m} \angle \mathrm{XOA}=0^{\circ}=0^c$
Its terminal arm (ray $O A)$ intersects the standard unit circle in $\mathrm{P}(1,0)$.
Hence, $\mathrm{x}=1$ and $\mathrm{y}=0$
$\sin 0^{\circ}=y=0$,
$\cos 0^{\circ}=x=1$,
$\tan 0^{\circ}=\frac{y}{x}=\frac{0}{1}=0$
$\cot 0^{\circ}=\frac{x}{y}=\frac{1}{0}$ which is not defined
$\sec 0^{\circ}=\frac{1}{x}=\frac{1}{1}=1$
$\cot 0^{\circ}=\frac{1}{y}=\frac{1}{0}$ which is not defined
Let $\mathrm{m} \angle \mathrm{XOA}=0^{\circ}=0^c$
Its terminal arm (ray $O A)$ intersects the standard unit circle in $\mathrm{P}(1,0)$.
Hence, $\mathrm{x}=1$ and $\mathrm{y}=0$
$\sin 0^{\circ}=y=0$,
$\cos 0^{\circ}=x=1$,
$\tan 0^{\circ}=\frac{y}{x}=\frac{0}{1}=0$
$\cot 0^{\circ}=\frac{x}{y}=\frac{1}{0}$ which is not defined
$\sec 0^{\circ}=\frac{1}{x}=\frac{1}{1}=1$
$\cot 0^{\circ}=\frac{1}{y}=\frac{1}{0}$ which is not defined
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