Find the value of: (2^ 0 +3^ -1 ) 3^2 - Vidyadip

Question

Find the value of:
$\big(2^{0}+3^{-1}\big)\times3^2$

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Answer

$(2^{0}+3^{-1})\times3^2$
$=\Big(1+\frac{1}{3}\Big)\times9$
$=\frac{3+1}{3}\times9$
$=\frac{4}{3}\times9$
$=12$

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