
$I_{1}=\frac{8}{5} \,A=1.6 \,A$
in loop $\mathrm{BCDEB}$
$I_{1}=\frac{3}{6}=0.5 \mathrm{\,A}$
$\mathrm{I}=-\left(\mathrm{I}_{1}+\mathrm{I}_{2}\right)$
$\mathrm{I}=-2.1 \mathrm{\,A}$



$STATEMENT-2$ Resistance of a metal increases with increase in temperature.

