Gujarat BoardEnglish MediumSTD 11 ScienceMATHSTRIGONOMETRIC FUNCTIONS2 Marks
Question
Find the value of sin 15°
✓
Answer
Here we have, sin 15° = sin (45° – 30°) = sin 45° cos 30° – cos 45° sin 30° $\begin{equation} =\frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2}-\frac{1}{\sqrt{2}} \times \frac{1}{2}=\frac{\sqrt{3}-1}{2 \sqrt{2}} \end{equation}$
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