$\therefore$ No of unpaired ${e}-({s})=0$
$\therefore \mu=\sqrt{n(n(n+2)}\,\, {BM}=0$
$[{n}=$ No of unpaired ${e}-({s})]$
In ${NiCl}_{2} {Ni}^{+2}$ is having configuration $3 {~d}^{8}$
$\therefore$ Number of unpaired electron $=2$
After formation of oxidised product
$\left[{Ni}({CN})_{6}\right]^{-2} {Ni}^{+4}$ is obtained
${Ni}^{{t}} \Rightarrow 3 {~d}^{6}$ and ${CN}^{-}$is strong field ligand
$\therefore$ number of unpaired electrons $=0$
$\therefore$ The charge is $2-0=2$
$(a)$ $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}\right]^{+}$
$(b)$ $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right) \mathrm{Cl}_{5}\right]^{-}$
$(c)$ $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}\left(\mathrm{NO}_{2}\right)\right]$
$(d)$ $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{ClBr}\right]^{2+}$
$(I)$ સિસ $- [Co(NH_3)_2(en)_2]^{3+}$ $(II)$ ટ્રાન્સ $-[IrCl_2(C_2O_4)_2]^{3-}$
$(III)\, [Rh(en)_3]^{3+}$ $(IV)$ સિસ $-[Ir(H_2O)_3Cl_3$
$(i)$ $\left[ M ( NCS )_{6}\right]^{(-6+ n )}$
$(ii)$ $\left[ MF _{6}\right]^{(-6+ n )}$
$(iii)$ $\left[ M \left( NH _{3}\right)_{6}\right]^{ n ^{+}}$