Question
फलन $\mathrm{f}(\mathrm{x})=2 \mathrm{x}+3(\mathrm{x})^{\frac{2}{3}}, \mathrm{x} \in \mathbb{R}$
$ f^{\prime}(x)=2+2 x^{\frac{-1}{3}} $
$ =2\left(1+\frac{1}{x^{\frac{1}{3}}}\right) $
$ =2\left(\frac{x^{\frac{1}{3}}+1}{x^{\frac{1}{3}}}\right) $
$ +\frac{1}{+}-\mathrm{m}^{-1}$
So, $\operatorname{maxima}(\mathrm{M})$ at $\mathrm{x}=-1$ $\operatorname{minima}(\mathrm{m})$ at $\mathrm{x}=0$
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