Question
$\mathop {\lim }\limits_{x \to \infty } \frac{{{x^n}}}{{{e^x}}} = 0$
$ = \mathop {\lim }\limits_{x \to \infty } \frac{{n\,\,!}}{{{e^x}}} = \frac{{n\,\,!}}{\infty } = 0$,
जहाँ $n\; = \,0,\;1,\;2,\;3......$
$( \because n! $ सभी धनात्मक पूर्णांकों तथा शून्य के लिये ही परिभाषित है)
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(जहाँ $S = p[{p^4} - 5{p^2}q + 5{q^2}],\,\;P = {p^2}{q^2}[{p^4} - 5{p^2}q + 4{q^2}]$