MCQ
Fluorine does not form positive oxidation states because
- ✓It is most electronegative element
- BIt forms only anions in ionic compounds
- CIt cannot form multiple bonding
- DIt shows non-bonded electron pair repulsion due to small size
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$A.\,\,F -CH_2\,\,CH_2\,\,COOH$
$\begin{array}{*{20}{c}}
{B.\,\,Cl - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$C.\,\,F -CH_2 -COOH$
$D.\,\,Br -CH_2-CH_2 -COOH$
Correct answer is
$Ag+ I^- \rightarrow AgI +e^-,$ $E^o = 0.152\, V$
$Ag \rightarrow Ag^+ +e^-,$ $E^o =-0.800\, V$
What is the value of log $K_{sp}$ for $AgI$ ? $(2. 303\, RT/F= 0. 059\, V)$
Reason : Lower the activation energy, faster is the reaction.