MCQ
Fluorine is a stronger oxidising agent than chlorine in aqueous solution. This is attributed to many factors except
- AHeat of dissociation
- ✓Electron affinity
- CHeat of hydration
- DIonisation potential
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If $E_{op}^o$ for this electrode is $1.30\,volt$ then what will be the oxidation electrode potential at $pH = 3$ ? .............. $\mathrm{volt}$