Following figure shows two processes $A$ and $B$ for a gas. If $\Delta Q_A$ and $\Delta Q_B$ are the amount of heat absorbed by the system in two cases, and $\Delta U_A$ and $\Delta U_B$ are changes in internal energies, respectively, then
JEE MAIN 2019, Medium
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Initial and final states for both the processes are same,
$\therefore \Delta \mathrm{U}_{\mathrm{A}}=\Delta \mathrm{U}_{\mathrm{B}}$
Work done during process $A$ is greater than in process $B$. Because area is more
By First law of thermodynamics
$\Delta Q=\Delta U+W$
$\Rightarrow \Delta \mathrm{Q}_{\mathrm{A}}>\Delta \mathrm{Q}_{\mathrm{B}}$
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