Following figures show different combinations of identical bulb$(s)$ connected to identical battery$(ies)$. Which option is correct regarding the total power dissipated in the circuit?
KVPY 2012, Diffcult
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(d)
Power consumed in each case is
$( Q )$ $P=\frac{V^2}{R / 3}=\frac{3 V^2}{R}$
$( P )$ $P=\frac{V^2}{3 R}$
$( R )$ $P=\frac{V^2}{R}$
$( S )$ $P=\frac{(2 V)^2}{R}=\frac{4 V^2}{R}$
So, order of increasing power consumption is $P > R > Q > S$.
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