Water of volume $2\, litre$ in a container is heated with a coil of $1\, kW$ at $27 \,^oC$. The lid of the container is open and energy dissipates at rate of $160\, J/s$. In how much time temperature will rise from $27\,^oC$ to $77\,^oC$ $[$ Given specific heat of water is $4.2\, kJ/kg$ $]$
IIT 2005, Medium
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Heat gained by water $=$ Heat supplied by container $-$ heat lost
$ \Rightarrow $ $mS\Delta \theta= 1000\,t -160\,t$
$ \Rightarrow $ $t = \frac{{2 \times 4.2 \times 1000 \times 50}}{{840}}$ = $8 \,\min \,20\, \sec$
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