MCQ
Following Kjeldahl's method, $1 \mathrm{~g}$ of organic compound released ammonia, that neutralised $10$ $\mathrm{mL}$ of $2 \mathrm{M} \ \mathrm{H}_2 \mathrm{SO}_4$. The percentage of nitrogen in the compound is_________ $\%$.
  • A
    $50$
  • $56$
  • C
    $70$
  • D
    $80$

Answer

Correct option: B.
$56$
b
$\mathrm{H}_2 \mathrm{SO}_4+2 \mathrm{NH}_3 \rightarrow\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4$

Millimole of $\mathrm{H}_2 \mathrm{SO}_4 \rightarrow 10 \times 2$

So Millimole of $\mathrm{NH}_3=20 \times 2=40$

Organic $\rightarrow$  $\mathrm{NH}_3$

Compound  40 Millimole

$\therefore$ Mole of $\mathrm{N}=\frac{40}{1000}$

wt. of $\mathrm{N}=\frac{40}{1000} \times 14$

$\%$ composition of $\mathrm{N}$ in organic compound

$=\frac{40 \times 14}{1000 \times 1} \times 100$

$=56 \%$

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