MCQ
Number of moles of methane required to produce $22 \mathrm{~g} \mathrm{CO}_{2(\mathrm{~g})}$ after combustion is $\mathrm{x} \times 10^{-2}$ moles. The value of $\mathrm{x}$ is
- A$30$
- B$40$
- ✓$50$
- D$60$
✓
Answer
Correct option: C.
$50$
c
$\mathrm{CH}_{4(\mathrm{~g})}+2 \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\ell)}$
$\mathrm{CH}_{4(\mathrm{~g})}+2 \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\ell)}$
$\mathrm{n}_{\mathrm{CO}_2}=\frac{22}{44}=0.5 \mathrm{moles}$
So moles of $\mathrm{CH}_4$ required $=0.5$ moles i.e. $50 \times 10^{-2} \mathrm{~mole}$
x=$50$
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