For a particle executing simple harmonic motion, the kinetic energy $K$ is given by $K = {K_o}{\cos ^2}\omega t$. The maximum value of potential energy is
A${K_0}$
B
Zero
C$\frac{{{K_0}}}{2}$
D
Not obtainable
Easy
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A${K_0}$
a (a) Since maximum value of ${\cos ^2}\omega t$ is $1$.
$\therefore {K_{\max }} = {K_o}{\cos ^2}\omega t = {K_o}$
Also ${K_{\max }} = P{E_{\max }} = {K_o}$
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