For a refrigerator, heat absorbed from source is $800\, J$ and heat supplied to sink is $500\, J$ then the coefficient of performance is
AIIMS 2019, Easy
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The expression for the coefficient of performance is,
Coefficient of performance $=\frac{Q_{2}}{Q_{1}-Q_{2}}$
Substitute 800 for $Q_{1}$ and 500 for $Q_{2}$ in above expression.
Coefficient of performance $=\frac{500}{800-500}$
$=\frac{5}{3}$
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