For a wire $\frac{R}{l}=\frac{1}{2}$ and length of wire is $l=5\, cm .$ If potential difference $1\, V$ is applied across it, current through wire will be: $( R =$ Resistance $)$ (in $A$)
AIIMS 2019, Medium
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The resistance of the wire is,
$R=\frac{l}{2}$
$=\frac{5 \times 10^{-2}}{2} \Omega$
The current through the wire will be,
$i=\frac{V}{R}$
$=\frac{1}{5 \times 10^{-2}} \times 2$
$=40 A$
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