MCQ
For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant $K$ is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is $\frac{3}{4} d$, where $'d'$ is the separation between the plates of parallel plate capacitor. The new capacitance $(C')$ in terms of original capacitance $\left( C _{0}\right)$ is given by the following relation
- A$C ^{\prime}=\frac{3+ K }{4 K } C _{0}$
- B$C ^{\prime}=\frac{4+ K }{3} C _{0}$
- ✓$C ^{\prime}=\frac{4 K }{ K +3} C _{0}$
- D$C ^{\prime}=\frac{4}{3+ K } C _{0}$
