For full scale deflection of total $50$ divisions, $50\,{mV}$ voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is $2\, {div} / {mA}$ will be $.....\Omega$
JEE MAIN 2021, Medium
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${I}_{\max }=\frac{50}{2}=25\, {mA}$
$R=\frac{V}{{I}}=\frac{50\, {mV}}{25\, {mA}}=2\, \Omega$
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