MCQ
For reaction
$
5 Br^{-}(aq)+BrO_3^{-}(aq)+6 H^{+} \rightarrow 3 Br_2(aq)+3 H_2 O(l)
$
The correct relation is :
  • A
    $\frac{ d \left[ Br _2\right]}{ dt }=\frac{4 d\left[ H _2 O \right]}{ dt }$
  • $-\frac{ d \left[ Br ^{-}\right]}{ dt }=\frac{-5}{6} \frac{d\left[ H ^{+}\right]}{ dt }$
  • C
    $-\frac{ d \left[ H ^{+}\right]}{ dt }=\frac{1}{2} \frac{d\left[ Br _2\right]}{ dt }$
  • D
    $-\frac{ d \left[ BrO _3^{-}\right]}{ dt }=\frac{1}{2} \frac{d\left[ H _2 O \right]}{ dt }$

Answer

Correct option: B.
$-\frac{ d \left[ Br ^{-}\right]}{ dt }=\frac{-5}{6} \frac{d\left[ H ^{+}\right]}{ dt }$
(B)Rate of reaction will be$-\frac{ d \left[ Br ^{-}\right]}{ dt }=\frac{-5}{6} \frac{d\left[ H ^{+}\right]}{ dt }$

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