For shown situation, in steady state condition ratio of charge stored in the first and last $n^{th}$ capacitor is
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$\mathrm{Q}_{1}=\mathrm{EC}, \mathrm{Q}_{\mathrm{n}}=\mathrm{E}(\mathrm{nC})=\mathrm{nQ}_{1} \Rightarrow \frac{\mathrm{Q}_{1}}{\mathrm{Q}_{\mathrm{n}}}=\frac{1}{\mathrm{n}}$
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