MCQ
For silve ${C_P}\,\left( {J{K^{ - 1}}\,mo{l^{ - 1}}} \right) = 23 + 0.01\,T$ . If the temperature $(T)$ of $3\, moles$ of silver is raised from $300\, K$ to $1000\, K$ at $1\, atm$ pressure, the value of $\Delta H$ will be close to.....$kJ$
  • A
    $13$
  • $62$
  • C
    $16$
  • D
    $21$

Answer

Correct option: B.
$62$
b
$\Delta H = n\int\limits_{{T_1}}^{{T_2}} {{C_{p.m}}dT = 3 \times \int\limits_{300}^{1000} {(23 + 0.01\,T)} } dT$

$ = 3[23(1000 - 300)] + \frac{{0.01}}{2}[{(1000)^2} - {(300)^2}]$

$ = 61950\,J \approx 62\,kJ$

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