MCQ
In Carius method $0.099 \,g$ organic compound gave $0.287\, g$ $AgCl$. The percentage of chlorine in the compound will be
- A$28.6$
- ✓$71.7$
- C$35.4$
- D$64.2$
= $\frac{{35.5}}{{143.5}} \times \frac{{0.287}}{{{\rm{0}}{\rm{.099}}}} \times 100 = 71.71\% $.
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$C{H_2} = C{H_2}\xrightarrow{{HBr}}X\xrightarrow[{{I_2}(excess)}]{\begin{subarray}{l}
Hydrolisis \\
N{a_2}C{O_3}
\end{subarray} }Z$
|
List$-I$ (Species) |
List$-II$ (Hybrid Orbitals) |
| $(a)$ $\mathrm{SF}_{4}$ | $(i)$ $\mathrm{sp}^{3} \mathrm{~d}^{2}$ |
| $(b)$ $\mathrm{IF}_{5}$ | $(ii)$ $\mathrm{d}^{2} \mathrm{sp}^{3}$ |
| $(c)$ $\mathrm{NO}_{2}^{+}$ | $(iii)$ $\mathrm{sp}^{3} \mathrm{~d}$ |
| $(d)$ $\mathrm{NH}_{4}^{+}$ | $(iv)$ $\mathrm{sp}^{3}$ |
| $(v)$ $\mathrm{sp}$ |
Choose the correct answer form the options given below :