MCQ
For the following reaction the mass of water produced from $445\,g$ of $C_{57}H_{110}O_6$ is .............. $\mathrm{g}$

$2{C_{57}}{H_{110}}{O_6}(s)\, + \,163\,{O_2}(g)\, \to \,114\,C{O_2}(g)\, + \,110\,{H_2}O(l)$

  • A
    $490$
  • B
    $445$
  • $495$
  • D
    $890$

Answer

Correct option: C.
$495$
c
$2{C_{57}}{H_{110}}{O_6}(s) + 163{O_2}(g) \to $ $114C{O_2}(g) + 110{H_2}O(l)$

$\frac{{Moles\,of\,{C_{57}}{H_{110}}{O_6}}}{2} = \frac{{Moles\,of\,{H_2}O}}{{110}}$

$\frac{{\frac{{445}}{{890}}}}{2} = \frac{{\frac{{Mass\,of\,{H_2}O}}{{18}}}}{{110}}$

Mass of $H_2O = 495\,g$

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