MCQ
For the following reactions the major products are shown 

${H_2}C = CH - CH = C{H_2}\xrightarrow[{0{\,^o}C}]{{HBr}}$ $\begin{array}{*{20}{c}}
  {{H_2}C = CH - CH - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,} 
\end{array}\xrightarrow{{ + 25{\,^o}C}}$ $\begin{array}{*{20}{c}}
  {C{H_2}CH = CHC{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$

These provide an example of  $......1......$ control at low temperature and $......2......$  control at higher temperature

  • $1 =$ kinetic  $2 =$ thermodynamic
  • B
    $1 =$ thermodynamic    $2 =$ kinetic
  • C
    $1 =$  kinetic  $2 =$ kinetic
  • D
    $1 = $ thermodynamic  $2 = $ thermodynamic

Answer

Correct option: A.
$1 =$ kinetic  $2 =$ thermodynamic
a
$(a)$ Low temperature kinetic control high temperature thermodynamic control.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free