$2N{O_2}(g) \rightleftharpoons {N_2}{O_4}(g)$ at $300\ K$
The value of $Kp$ is $2\ atm^{-1}$ . The total pressure at equilibrium is $10\ atm$ . If volume of container become two times of its original volume, what will be its equilibrium pressure at $300\ K$ ......$atm$
$\mathrm{kp}=\frac{\mathrm{P}_{2}}{\mathrm{P}_{1}^{2}}=2......(i)$
$\mathrm{P}_{1}+\mathrm{P}_{2}=10......(ii)$
$\mathrm{P}_{2}=8 \,\mathrm{atm} \quad \mathrm{P}_{1}=2 \,\mathrm{atm}$
$\mathop {2{\text{N}}{{\text{O}}_2}}\limits_{(1 + 2P)} \quad \rightleftharpoons \quad \mathop {{{\text{N}}_2}{{\text{O}}_4}}\limits_{(4 + P)} $
$\mathrm{P}_{\mathrm{T}}=(5+\mathrm{P})$
$K_{p}=\frac{(4-P)}{(1+2 P)^{2}}=2$
$\mathrm{P}=0.19\, \mathrm{atm}$
$\mathrm{P}_{\mathrm{T}}=5.19\, \mathrm{atm}$
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