MCQ
For the reaction at $300\,K$

$A(g) + B(g) \to C(g)$  $\Delta U=\,-\,3\,Kcal$

                                             $\Delta S=\,-\,10\,cal/K$

value of $\Delta G$ will be ......$cal$

  • $-600$
  • B
    $-6600$
  • C
    $-6000$
  • D
    $-60$

Answer

Correct option: A.
$-600$
a
Correct optlon (A) 600 cal

Explanatlon:

$A ( g )+ B ( g ) \rightarrow C$

$\Delta E=-3 k Cal$

$\Delta H =\Delta E +\Delta_{ ng } R$

$=-3-\frac{1 \times 1.987 \times 300}{1000}$

$\Delta H =-3.60$

$\Delta H =\Delta H - T \Delta S$

$=-3.5+\frac{300 \times-10}{1000} 0.6 k cal$

$\Rightarrow 600 cal$

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