MCQ
For the reaction equilibrium ${N_2}{O_4}$ $\rightleftharpoons$ $2N{O_{2(g)}}$, the concentrations of ${N_2}{O_4}$ and $N{O_2}$ at equilibrium are $4.8 \times {10^{ - 2}}$and $1.2 \times {10^{ - 2}}\,mol\,litr{e^{ - 1}}$ respectively. The value of ${K_c}$ for the reaction is
  • A
    $3.3 \times {10^2}$ $mol\,\,litr{e^{ - 1}}$
  • B
    $3 \times {10^{ - 1}}$ $mol\,\,litr{e^{ - 1}}$
  • $3 \times {10^{ - 3}}$ $mol\,\,litr{e^{ - 1}}$
  • D
    $3 \times {10^3}$ $mol\,\,litr{e^{ - 1}}$

Answer

Correct option: C.
$3 \times {10^{ - 3}}$ $mol\,\,litr{e^{ - 1}}$
(c) $K = \frac{{{{[N{O_2}]}^2}}}{{[{N_2}{O_4}]}}$$ = \frac{{{{[1.2 \times {{10}^{ - 2}}]}^2}}}{{[4.8 \times {{10}^{ - 2}}]}}$$ = 0.3 \times {10^{ - 2}}$$ = 3 \times {10^{ - 3}}$

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