MCQ
$\ce{I.P}$. of sodium is $\ce{5.14 eV}$ then $\ce{I.P.}$ of potassium will be :
  • A
    Equal to sodium
  • B
    $\ce{5.68 eV}$
  • $\ce{4.34 eV}$
  • D
    $\ce{10.28 eV}$

Answer

Correct option: C.
$\ce{4.34 eV}$
$\ce{I.P}$. of sodium is $\ce{5.14 eV}$ then $\ce{I.P}$. of potassium will be $\ce{4.34 eV}$. On moving down a group, the ionization potential decreases.
Hence, the ionization potential of potassium should be lower than the ionization potential of sodium.

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