MCQ
$\ce{I.P}$. of sodium is $\ce{5.14 eV}$ then $\ce{I.P.}$ of potassium will be :
- AEqual to sodium
- B$\ce{5.68 eV}$
- ✓$\ce{4.34 eV}$
- D$\ce{10.28 eV}$
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