$NH_3{_{(g)}}\ \rightleftharpoons \ \frac {1}{2} {N_2}_{(g)} + \frac {3}{2} {H_2}_{(g)}$ ; $K_P$
The degree of dissociation $(\alpha )$ of $NH_3$ is related to total equilibrium pressure $(P^o )$ as
- ✓$\alpha = {\left( {1 + \frac{{3\sqrt 3 {P^o}}}{{4{K_P}}}\,} \right)^{ - \frac{1}{2}}}$
- B$\alpha = {\left( {1 + \frac{{3\sqrt 3 {P^o}}}{{4{K_P}}}\,} \right)^{\frac{1}{2}}}$
- C$\alpha = {\left( {1 + \frac{{3{P_0}}}{{4{K_P}}}\,} \right)^{\frac{1}{2}}}$
- D$\alpha = {\left( {1 + \frac{{3{P_0}}}{{4{K_P}}}\,} \right)^{ - \frac{1}{2}}}$
