MCQ
For the reaction, $PC{l_{3(g)}}$ $+$ $C{l_{2(g)}}$ $\rightleftharpoons$ $PC{l_{5(g)}}$, the value of ${K_c}$ at $250\,^oC$ is $ 26$. The value of ${K_p}$ at this temperature will be
- ✓$0.61$
- B$0.57$
- C$0.83$
- D$0.46$
✓
Answer
Correct option: A.
$0.61$
(a)${K_p} = {K_c}{[RT]^{\Delta n}};\,\,\Delta n = - 1,\,\,{K_c} = 26$
$R = 0.0812,\,T = 250 + 273 = 523\,K$
${K_p} = 26{[0.0812 \times 523]^{ - 1}} = 0.605 \approx 0.61$
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