MCQ
For the reaction, $\text{CO(g)}+\text{ClO}_2\text{(g)}\rightleftharpoons\text{COCl}_2(\text{g}),$ the $\frac{\text{K}_{\text{p}}}{\text{K}_\text{C}}$ is equal to :
  • A
    $\sqrt{\text{RT}}$
  • B
    $\text{RT}$
  • $\frac{1}{\text{R.T}}$
  • D
    $1.0$

Answer

Correct option: C.
$\frac{1}{\text{R.T}}$
$\text{K}_{\text{p}}=\text{K}_{\text{C}}(\text{RT})^{\Delta\text{n}}$
$\Rightarrow\text{K}_{\text{p}}=\text{K}_{\text{C}}(\text{RT})^{1-2}$
$\Rightarrow\frac{\text{K}_{\text{p}}}{\text{K}_{\text{C}}}=\frac{1}{\text{RT}}$

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