MCQ
For the reaction${H_2} + {I_2} = 2HI$, the equilibrium concentration of ${H_{2\,}},\,{I_2}$ and $HI$ are $8.0$, $3.0$ and $28.0$ $mol \,per\, litre$ respectively, the equilibrium constant of the reaction is
  • A
    $30.66$
  • $32.66$
  • C
    $34.66$
  • D
    $36.66$

Answer

Correct option: B.
$32.66$
(b) ${K_c} = \frac{{{{[HI]}^2}}}{{[{H_2}]\,\,[{I_2}]}} = \frac{{{{(28)}^2}}}{{8 \times 3}} = 32.66$

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