MCQ
For which natural number $n, 6^n$ ends with digit zero?
- A6
- B5
- C0
- ✓None
✓
Answer
Correct option: D.
None
(d)
Since $6^{ n }$ is expressed as $(2 \times 3)^{ n }$, it can never end with digit 0 as it does not have 5 in its prime factorisation.
Since $6^{ n }$ is expressed as $(2 \times 3)^{ n }$, it can never end with digit 0 as it does not have 5 in its prime factorisation.
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