Force constant of a spring $(K)$ is synonymous to
Diffcult
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$\mathrm{Y}=\frac{\mathrm{FL}}{\mathrm{A} \Delta \mathrm{L}}$
Or $\mathrm{F}=\left(\frac{\mathrm{YA}}{\mathrm{L}}\right) \Delta \mathrm{L}$
Comparing this with $\mathrm{F}=\mathrm{K} \Delta \mathrm{L}$
$\mathrm{K}=\frac{\mathrm{YA}}{\mathrm{L}}$
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