A rod of uniform cross-sectional area $A$ and length $L$ has a weight $W$. It is suspended vertically from a fixed support. If Young's modulus for rod is $Y$, then elongation produced in rod is ......
Easy
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(b)
Center of mass is at $\frac{L}{2}$ distance from top so it can be assumed for easy calculation that $W$ weight is hanged to a $\frac{L}{2}$ length string
Now use $\frac{F L}{A Y} \cdot \Delta L$
$\Delta L=\frac{W \times L}{2 A Y}$
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