Force constant of a spring $(K)$ is synonymous to
  • A$\frac{YA}{L}$
  • B$\frac{YL}{A}$
  • C$\frac{AL}{Y}$
  • D$ALY$
Diffcult
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    There are two wires of same material and same length while the diameter of second wire is $2$ times the diameter of first wire, then ratio of extension produced in the wires by applying same load will be 
    View Solution
  • 2
    The bulk modulus of an ideal gas at constant temperature
    View Solution
  • 3
    On applying a stress of $20 \times {10^8}N/{m^2}$ the length of a perfectly elastic wire is doubled. Its Young’s modulus will be
    View Solution
  • 4
    The compressibility of a material is
    View Solution
  • 5
    A wire is loaded by $6\, kg$ at its one end, the increase in length is $12\, mm.$ If the radius of the wire is doubled and all other magnitudes are unchanged, then increase in length will be ......... $mm$
    View Solution
  • 6
    Given below are two statements: One is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.

    Assertion $(A)$:The stretching of a spring is determined by the shear modulus of the material of the spring.

    Reason $(R)$:A coil spring of copper has more tensile strength than a steel spring of same dimensions.

    In the light of the above statements, choose the most appropriate answer from the options given below:

    View Solution
  • 7
    The breaking stress of wire going over a smooth pully is $2 \times 10^9\, N/m^2$. What would be the minimum radius of wire used if it is not to break?
    View Solution
  • 8
    Two similar wires under the same load yield elongation of $0.1$ $mm$ and $0.05$ $mm$ respectively. If the area of cross- section of the first wire is $4m{m^2},$ then the area of cross section of the second wire is..... $mm^2$
    View Solution
  • 9
    When a force is applied on a wire of uniform cross-sectional area $3 \times {10^{ - 6}}\,{m^2}$ and length $4m$, the increase in length is $1\, mm.$ Energy stored in it will be $(Y = 2 \times {10^{11}}\,N/{m^2})$
    View Solution
  • 10
    A string of area of cross-section $4\,mm ^{2}$ and length $0.5$ is connected with a rigid body of mass $2\,kg$. The body is rotated in a vertical circular path of radius $0.5\,m$. The body acquires a speed of $5\,m / s$ at the bottom of the circular path. Strain produced in the string when the body is at the bottom of the circle is $\ldots . . \times 10^{-5}$. (Use Young's modulus $10^{11}\,N / m ^{2}$ and $g =10\,m / s ^{2}$ )
    View Solution