Four capacitors are connected as shown in the equivalent capacitance between the points $P$ and $Q$ is.......$\mu F$
A$4$
B$0.25$
C$0.75$
D$1.33$
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D$1.33$
d (d) ${C_{PQ}} = \frac{1}{3}\,\mu F + 1\,\mu F = \frac{4}{3}\,\mu F$
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