Four equal resistance dissipated $5 \,W$ of power together when connected in series to a battery of negligible internal resistance. The total power dissipated in these resistance when connected in parallel across the same battery would be ........... $W$
A$125$
B$80$
C$20$
D$5$
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B$80$
b (b)
$\frac{P}{4}=5$
$P=20$
$4(20)=80 \,W$
Net power in parallel
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