Four metallic plates arearranged as shown in the figure. If the distance between each plate then capacitance of the given system between points $A$ and $B$ is (Given $d < < A$)
Medium
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There will have two capacitors in between $A$ and $B$ and they are in parallel combination.
The capacitance of parallel plate capacitor is $C=\frac{A \epsilon_{0}}{d}$
The capacitance in between $\mathrm{A}$ and $\mathrm{B}$ is $C_{A B}=C+C=2 C=\frac{2 A \epsilon_{0}}{d}$
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